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2-2x+0.25x^2=0
a = 0.25; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·0.25·2
Δ = 2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{2}}{2*0.25}=\frac{2-\sqrt{2}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{2}}{2*0.25}=\frac{2+\sqrt{2}}{0.5} $
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